t=2t^2+20t+10042

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Solution for t=2t^2+20t+10042 equation: 



t=2t^2+20t+10042

We move all terms to the left:

t-(2t^2+20t+10042)=0

We get rid of parentheses

-2t^2+t-20t-10042=0

We add all the numbers together, and all the variables

-2t^2-19t-10042=0

a = -2; b = -19; c = -10042;
Δ = b2-4ac
Δ = -192-4·(-2)·(-10042)
Δ = -79975
Delta is less than zero, so there is no solution for the equation

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